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The figure shows two large, closely para...

The figure shows two large, closely parallel, nonconducting sheets with identical (positive) uniform surface charge densities and a sphere with a uniform (positive) volume charge density. Four points marked as `1,2,3` and 4 are shown in the space in between. If `E_(1),E_(2),E_(3)` and `E_(4)` are magnitude of net electric fields at these points respectively then :

A

`E_(1) gt E_(2) gt E_(3) gt E_(4)`

B

`E_(1) gt E_(2) gt E_(3) = E_(4)`

C

`E_(3) = E_(4) gt E_(2) gt E_(1)`

D

`E_(1) = E_(2) = E_(3) = E_(4)`

Text Solution

Verified by Experts

The correct Answer is:
C

Electric field due to both the plates will be cancelled out for all the points. So the net electric field at the points will be governed only by the sphere, Farther the point from the sphere, lesser the magnitude of electric field. Therefore `E_(3) = E_(4) gt E_(2) gt E_(1)`.
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Knowledge Check

  • The figure shows two large, closely placed, parallel, nonconducting sheets with identical (positive) uniform surface charge densities, and a sphere with a uniform (positive) volume charge density. Four points marked as 1,2,3, and 4 are shown in the space in between. If E_1, E_2, E_3, and E_4 are magnitude of net electric fields at these points, respectively, then

    A
    `E_1gtE_2gtE_3gtE_4`
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    `E_1gtE_2gtE_3=E_4`
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    `E_3 = E_4gtE_2gtE_1`
    D
    `E_1=E_2=E_3=E_4`

  • The figure show four situations in which charged particles are at equal distances from the origin. If E_1,E_2,E_3 and E_4 be the magnitude of the net electic field at the origin in four situations i, ii, iii and iv respectively then

    A
    `E_1=E_2=E_3=E_+4`
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    `E_1=E_2gtE_3gtE_4`
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