A conductor has `14.4 xx 10^(-19)` coulombs positive charge. The conductor has : (Charge on electron `= 1.6 xx 10^(-19)` coulombs

Options

A. 9 electron in excess
B. 27 electron in short
C. 27 electrons in excess
D. 9 electrons in short

Explanation

To find the number of electrons ejected from a conductor that has a positive charge of \( 14.4 \times 10^{-19} \) coulombs, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Charge of One Electron**:
The charge of one electron is given as \( 1.6 \times 10^{-19} \) coulombs.

2. **Determine the Total Positive Charge**:
The total positive charge on the conductor is \( 14.4 \times 10^{-19} \) coulombs.

3. **Calculate the Number of Electrons Ejected**:
To find the number of electrons ejected, we can use the formula:
\[ \text{Number of electrons} = \frac{\text{Total positive charge}}{\text{Charge of one electron}} \]
Substituting the values:
\[ \text{Number of electrons} = \frac{14.4 \times 10^{-19}}{1.6 \times 10^{-19}} \]

4. **Perform the Division**:
When we divide the two quantities:
\[ \text{Number of electrons} = \frac{14.4}{1.6} = 9 \]

5. **Conclusion**:
Therefore, the number of electrons ejected from the conductor is \( 9 \).

### Final Answer:
The conductor has ejected **9 electrons**.