Home
Class 12
PHYSICS
AB and CD are two uniform resistance wir...

`AB` and `CD` are two uniform resistance wires of lengths `100 cm` and `80 cm` respectively. The connections are shown in the figure. The cell of emf `5 V` is ideal while the other cell of `E` has internal resistance `2 Omega`. A length of `20 cm` of wire `CD` is balanced by `40 cm` of wire `AB`. Find the emf `E` in volt, if the reading of the ideal ammeter is `2 A`. The other connecting wires have negligible resistance

Text Solution

Verified by Experts

The correct Answer is:
12

Potential difference across wire AB = 5V
`:.` p.d across 40 cm of this wire `= (5)/(100) xx 40`
= 2 volt
`:.` Potential difference across 20 cm of wire CD = 2 volt
`:.` p.d across wire `CD =(2)/(20)xx80=8` volt
p.d across `2 Omega` resistance `= 2 xx 2 = 4` volt
`:.` Emf of the cell = 12 volt.
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.38|20 Videos
  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.39|9 Videos
  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.36|20 Videos
  • CURRENT ELECTRICITY

    RESONANCE|Exercise High Level Problems (HIP)|21 Videos
  • ELECTRO MAGNETIC WAVES

    RESONANCE|Exercise Exercise 3|27 Videos

Similar Questions

Explore conceptually related problems

A resistance of 4 Omega and a wire of length 5 meters and resistance 5 Omega are joined in series and connected to a cell of e.m.f. 10 V and internal resistance 1 Omega . A parallel combination of two identical cells is balanced across 300 cm of wire. The e.m.f. E of each cell is

AB is a potentiometer wire of length 100 cm and its resistance is 10Omega . It is connected in series with a resistance R = 40 Omega and a battery of emf 2 V and negligible internal resistance. If a source of unknown emf E is balanced by 40 cm length of the potentiometer wire, the value of E is

A potentiometer wire of length 100 cm having a resistance of 10 Omega is connected in series with a resistance R and a cell of emf 2V of negligible internal resistance. A source of emf of 10 mV is balanced against a length of 40 cm of the potentiometer wire. What is the value of resistance R ?

A potentiometer wire has resistance of per unit length of 0.1Omega//m . A cell of e.m.f. 1.5V balances against 300cm length of the wire. Find the current in the potentiometer wire.

AB is a potentiometer wire of length 100 cm and its resistance is 10 ohms . It is connected in series with a resistance R = 10 ohms and a battery of e.m.f. 2 V and negligible internal resistance. If a source of unknown e.m.f. E is balanced by 40 cm length of the potentiometer wire, the value of E is

A potentiometer wire of length 4 cm has a some resistance. The resistance connected in series with the wire and accumulator of e.m.f. 2V is 16Omega . If the potential gradient along wire is 10^(-3)V//cm . The resistance of potentiometer wire is