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An electron orbiting around a nucleus ha...

An electron orbiting around a nucleus has angular momentum L. The magnetic field produced by the electron at the centre of the orbit can be expressed as :

A

`B = (mu_(0) e//8pi mr^(3))L`

B

`B =(mu_(0)e//4 pi mr^(3))L`

C

`B = (mu_(0) e//pi mr^(3))L`

D

`B =(e//4 pi epsilon_(0) mr^(3))L`

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The correct Answer is:
To find the magnetic field produced by an electron orbiting around a nucleus in terms of its angular momentum \( L \), we can follow these steps: ### Step 1: Understand the relationship between angular momentum and the electron's motion The angular momentum \( L \) of an electron in a circular orbit can be expressed as: \[ L = m v r \] where \( m \) is the mass of the electron, \( v \) is its tangential velocity, and \( r \) is the radius of the orbit. ### Step 2: Write the expression for the magnetic field The magnetic field \( B \) produced by a moving charge (the electron) at a point in space can be expressed using the Biot-Savart law. For a circular current loop, the magnetic field at the center is given by: \[ B = \frac{\mu_0 I}{2r} \] where \( I \) is the current due to the moving charge and \( r \) is the radius of the orbit. ### Step 3: Relate current \( I \) to the motion of the electron The current \( I \) due to the electron can be defined as the charge passing through a point per unit time. For an electron moving in a circular path: \[ I = \frac{q}{T} \] where \( q \) is the charge of the electron (denoted as \( e \)), and \( T \) is the time period of one complete revolution. The time period \( T \) can be expressed as: \[ T = \frac{2\pi r}{v} \] Thus, the current becomes: \[ I = \frac{e}{T} = \frac{e v}{2\pi r} \] ### Step 4: Substitute the expression for current into the magnetic field formula Substituting \( I \) into the magnetic field expression: \[ B = \frac{\mu_0}{2r} \cdot \frac{e v}{2\pi r} = \frac{\mu_0 e v}{4\pi r^2} \] ### Step 5: Express \( v \) in terms of \( L \) From the angular momentum expression \( L = m v r \), we can solve for \( v \): \[ v = \frac{L}{m r} \] Substituting this expression for \( v \) into the magnetic field equation: \[ B = \frac{\mu_0 e}{4\pi r^2} \cdot \frac{L}{m r} = \frac{\mu_0 e L}{4\pi m r^3} \] ### Final Expression Thus, the magnetic field produced by the electron at the center of the orbit can be expressed as: \[ B = \frac{\mu_0 e L}{4\pi m r^3} \]

To find the magnetic field produced by an electron orbiting around a nucleus in terms of its angular momentum \( L \), we can follow these steps: ### Step 1: Understand the relationship between angular momentum and the electron's motion The angular momentum \( L \) of an electron in a circular orbit can be expressed as: \[ L = m v r \] where \( m \) is the mass of the electron, \( v \) is its tangential velocity, and \( r \) is the radius of the orbit. ...
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