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A short bar magnet is placed along N-S d...

A short bar magnet is placed along N-S direction with N pole pointing north. The neutral points are located 20 cm away from the bar magnet. If `B_(H)` is the horizontal component of earth's magnetic field then the magnetic field due to the bar magnet at distance of 40 cm along its axis is

A

`(B_(H))/(2)`

B

`(B_(H))/(4)`

C

`(B_(H))/(8)`

D

`(B_(H))/(16)`

Text Solution

Verified by Experts

The correct Answer is:
C

`B prop (1)/(r^(3))`
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