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A uniform thin rod of mass 'm' and lengt...

A uniform thin rod of mass 'm' and length '3l' is released from rest from horizontal position as shown. When it passes through the vertical line AD, it gets broken at point 'C' without jerk. Find the angle (in radian) rotated by rod BC till its centre of mass passes through the horizontal line PQ frm the instant of breakage `(g = 10 m//s^(2))` (hinge is smooth)

Text Solution

Verified by Experts

The correct Answer is:
4 radians
By energy conservation,
`mg. (3l)/(2) = (1)/(2) (m (3l)^(2))/(3) omega^(2) " " omega = sqrt((g)/(l))`
If time taken by centre of mass of rod BC from breaking position to line PQ is t.
`theta = omega.t = 4` radian
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