If `alpha+beta-gamma=pi` and `sin^2alpha+sin^2beta-sin^2gamma=lambda sinalpha sinbeta cosgamma,` then write the value of `lambda`

Explanation

To solve the problem, we need to find the value of \( \lambda \) given the equations:

1. \( \alpha + \beta - \gamma = \pi \)
2. \( \sin^2 \alpha + \sin^2 \beta - \sin^2 \gamma = \lambda \sin \alpha \sin \beta \cos \gamma \)

### Step-by-step Solution:

**Step 1: Rewrite the first equation.**
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