The value of `sin^2 75^0-sin^2 15^0` is `1//2` b. `sqrt(3)//2` c. 1 d. 0

Explanation

To solve the problem \( \sin^2 75^\circ - \sin^2 15^\circ \), we can follow these steps:

### Step 1: Rewrite \( \sin^2 75^\circ \)
We know that \( 75^\circ = 90^\circ - 15^\circ \). Therefore, we can use the identity \( \sin(90^\circ - \theta) = \cos(\theta) \):
\[ \sin^2 75^\circ = \sin^2(90^\circ - 15^\circ) = \cos^2 15^\circ \]

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