Find the equation of the circle which has its centre at the point (3,4) and touches the straight line `5x+12 y-1=0.`

Explanation

To find the equation of the circle with its center at the point (3, 4) that touches the straight line \(5x + 12y - 1 = 0\), we can follow these steps:

### Step 1: Identify the center of the circle and the equation of the line
The center of the circle is given as \(C(3, 4)\) and the line is given by the equation \(5x + 12y - 1 = 0\).

### Step 2: Find the perpendicular distance from the center to the line
The radius of the circle is equal to the perpendicular distance from the center of the circle to the line. The formula for the perpendicular distance \(d\) from a point \((x_0, y_0)\) to a line \(Ax + By + C = 0\) is given by:

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