The circle `x^2+y^2-2x-2y+1=0` is rolled along the positive direction of x-axis and makes one complete roll. Find its equation in new position.

Explanation

[ # XI_RD_24_028]


`x^{2}+y^{2}-2 x-2 y+1=0`


`(x^{2}-2 x+1)+(y^{2}-2 y+1)=1 `


`(x-1)^{2}+(y-1)^{2}=1` .


New ` r=1 `


`C(1+2 pi, 1)`


`[(x-(1+2 pi)^{2}+(y-1)^{2}]=(1)^{2}.`


`x^{2}+(1+2 pi)^{2}-2 x(1+2 pi)+y^{2}+1 -2 y=1 `


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