A sound wave of frequency 500 Hz covers a distance of 1000 m is 5 sec between the points X and Y. Then the number of waves between X and Y is
A
500
B
1000
C
2500
D
5000
Text Solution
Verified by Experts
The correct Answer is:
C
`V=1000/5=200 m//s` `V=n lambdarArr lambda=V/n=200/500` No. of wave `=L/(lambda)=(1000xx500)/200=2500`
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