The sound intensity is `0.008W//m^( 2)` at a distance of 10 m from an isotropic point source of sound. The power of the source is
A
2.5 w
B
0.8 w
C
8 w
D
10 w
Text Solution
Verified by Experts
The correct Answer is:
D
`P/(4pir^(2))`=1 for an isotropic point sound source, `rArr F=L 4pir^(2)` `=(0.008w//m^(2))(4.pi.10^(2))` =10 watt
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