The faintest sound the human ear can detect at a frequency of ` kHz` (for which ear is most sensitive) corresponds to an intensity of about `10^(-12)w//m^(2)`. Assuming the density of air `cong1.5kg//m^(3)` and velocity of sound in air `cong300m//s`, the pressure amplitude and displacement amplitude of the sound will be rspectively ____`N//m^(2)` and ____`m`.
If the density of air at NTP is 1.293kg//m^(3) and gamma=1.41 , then the velocity of sound in air at NTP is :
A blast given a sound of intensity 0.8 W//m^(2) at frequency 1kHz. If the denstiy of air is 1.3 kg//m^(3) and speed of sound in air is 330 m/s, then the amplitude of the sound wave is approximately
The faintest sound the human ear can detect at a frequency of 1000 Hz correspond to an intensity of about 1.00xx10^-12(W)/(m^2) , which is called threshold of hearing. The loudest sounds the ear can tolerate at this frequency correspond to an intensity of about 1.00(W)/(m^2) , the threshold of pain. Detemine the pressure amplitude and displacement amplitude associated with these two limits. Take speed of sound =342(m)/(s) and density of air =1.20(kg)/(m^3)
The velocity of sound in air is 340m/s . If the density of air is increased to 4 times, the new velocity of sound will be
The velocity of sound in air is 330 m//s . Then the frequency that will resonate with an open pipe of length 1m is –
In the previous example, if the density of air r = 1 . 22 kg //m^(3) , then find the intensity of a sound wave of the largest amplitude tolerable to the human ear.
What is the level of loudness of a sound of intensity 10^(-12) W//m^2 ?
Velocity of sound in air is 320 m//s . The resonant pipe shown in Fig. 7.81 cannot vibrate with a sound of frequency .
The length of an open pipe is 0.5m and the velocity of sound in air is 332 m//sec . The fundamental frequency of the pipe is
