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In a transistor connected in a common em...

In a transistor connected in a common emitter mode `R_C = 4kOmega, R_1 = 1kOmega, I_C = 1mA` and `I_B = 20 muA`. Find the voltage gain.

A

50

B

200

C

`1/50`

D

`1/200`

Text Solution

Verified by Experts

The correct Answer is:
B
`A_(v)=(beta_(ac)R R_(c))/(R_(1))=(I_(e))/(I_(B)).(R_(C))/(R_(1))=(10^(-3)xx4xx10^(3))/(20xx10^(-6)xx10^(3))=200`
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