An X-ray tube operates at 20 kV. A particular electron loses 5% of its kinetic energy to emit an X-ray photon at the first collision. Find the wavelength corresponding to this photon.

Explanation

kinetic energy acquired by the electron is
`k=Ev=20XX10^(3) eV`
The energy of the photon
`K=eV=20xx10^(3)eV`
The energy of the photon
`0.05xx20=10^(3)eV=10^(3)eV`.
Thus, `(hv)/(lambda)=10^(3)eV=((4.14xx10^(-15)eV-s)xx(3xx10^(8)m//s))/(10^(3)eV)=(1242eV9nm)/(10^(3)eV)=1.24 nm`