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The kinetic energies of photoelectrons r...

The kinetic energies of photoelectrons range from zero to `4.0xx10^(-19)J` when light of wavelength `3000 Å` falls on a surface. What is the stopping potential for this light?

Text Solution

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`K_(max)=4.0xx10^(-19)Jxx(1eV)/(1.6xx10^(-19))=2.5 eV`.
Then, from `eV_(s)=K_(max),V_(s)=2.5V`
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