A particle of mass `M` at rest dacays into two particle of masses `m_(1)` and `m_(2) `having non zero velocity . The ratio of the de Broglie wavelength . The ratio of the de Broglie wavelength of the particle `lambda , _(1) // lambda_(2)` is

Options

A. `(m_(1))/(m_(2))`
B. `(m_(2))/(m_(1))`
C. `1:1`
D. `sqrt((m_(2))/(m_(1)))`

Answer

C

Explanation

`lambda=(h)/(p)`
Since the momenta of the two particles are equal `lambda` are same.