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`underset(underset(underset(underset(underset("Fructose")(CH_(2)OH))(|))((CHOH)_(3)))(|)) overset(overset(CH_(2)OH)(|))(C)=O overset(NaBH_(4))(rarr) A +B`
The product `A` and `B` in the a above reaction are

A

Diastereomers

B

`C-2` epimers

C

Anomers

D

Optically active hexahydroxy compounds

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

`A` and `B` differ in configuration at `C-2` hence they are epimers, also they are non mirror images as `C-3,C-4,C-5` have same configuration, hence they are diastereomers. `A` and `B` both are optically active.
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