For what value of `lambda` is the function `f(x)={lambda(x^2-2x)\ \ \ \ ,\ \ \ \ if\ xlt=0 4x+1\ \ \ \ ,\ \ \ \ if\ x >0` continuous at `x=0` ? What about the continuity at `x=+-1` ?

Explanation

If f is continuous at `x=0`,
then

`lim_(x→0−)​f(x)=lim​_(x→0+)f(x)=f(0)`


`=>lim_(x→0)​λ(x^2−2x)`

`=>lim_(x→0)​(4x+1)`

`=>λ(0^2−2x0)`

`=>λ(0^2−2**0)`

`=>4⋅0+1`

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