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N(2)+3H(2)hArr2NH(3) if in equilibrium m...

`N_(2)+3H(2)hArr2NH_(3)` if in equilibrium mixture by volume `N_(2)` is `40%, H_(2)` is `30%` and rest is `NH_(3)` and total pressure is 5 atm then find out `K_(p)`:-

A

`(1)/(300)`

B

`(1)/(3)`

C

`(1)/(30)`

D

`(2)/(3)`

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The correct Answer is:
B
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