If `V_(1)mL` of `C_(1)` solution `+V_(2)mL` of `C_(2)` solution are mixed together then calculate final concentration of solution and final osmotic pressure. If initial osmotic pressure of two solutions are `pi_(1)` and `pi_(2)` respectively?

Answer

`pi=((pi_(1)V_(1)+pi_(2)V_(2))/(V_(1)+V_(2)))`

Explanation

`C_(t)=(C_(1)V_(1)+C_(2)V_(2))/(V_(1)+V_(2))`
`pi_(1)=C_(1)RT, C_(1)=((pi_(1))/(RT)) , pi_(2)=C_(2)RT, C_(2)=((pi_(2))/(RT))`
`pi=((C_(1)V_(1)+C_(2)V_(2))/(V_(1)+V_(2)))RT`
`pi=((pi_(1)V_(1)+pi_(2)V_(2))/(V_(1)+V_(2)))`