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Mole fraction of C(3)H(5)(OH)(3) in a so...

Mole fraction of `C_(3)H_(5)(OH)_(3)` in a solution of `36g` of water and `46g` of glycerine is:

A

`0.46`

B

`0.36`

C

`0.20`

D

`0.40`

Text Solution

Verified by Experts

The correct Answer is:
C
Mole of `H_(2)O=(36)/(18)=2`
Mole of glycerine `=(46)/(92)=0.5` total mole `=2+0.5=2.5`
Mole fractions of glycerine `=(n_(1))/(n_(1)+n_(2))=(0.5)/(2.5)rArr X_(0)=0.2`
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