A complex containing `K^(+),Pt(IV)` and `Cl^(--)` is `100%` ionised giving `i=3`. Thus, complex is:

Options

A. `K_(2)[PtCl_(4)]`
B. `K_(2)[PtCl_(6)]`
C. `K_(43)[PtCl_(5)]`
D. `K[PtCl_(3)]`

Answer

B

Explanation

`i=` van't Hoff factor `=1+(y-1)x`
(y=` number of ions, `x=` degree of ionisation)
`y i=1+(y-1)x`
(a) `K_(2)PlCI_(4) 2K^(+)+PlCl_(4^(2-)) 3 1+2=3`
(b) K_(2)PlCl_(6) 2K^(+)+PlCl_(6^(2-) 3 3`
In (a), oxidation number of `Pt=2`
In (b) oxidation number of `Pt=4`