An aqueous solution of a solute AB has b.p. of `101.08^(@)C( AB` is `100%` ionised at boiling point of the solution ) and freezes at `-1.80 ^(@)C`. Hence, `AB(K_(b)//K_(f)=0.3)`

Options

A. is `100%` ionised at the `f.p.` of the solution
B. behaves as non-electrolyte at the `f.p.` of the solution
C. forms dimer
D. None of the above

Answer

B

Explanation

Given `DeltaG_(b)=1.08^(@)C, i=2` at boiling pt. of solution.
and `DeltaT_(f)=1.80^(@)C`, and `(k_(b))/(K_(f))=0.3`
so `(DeltaT_(b))/(DeltaT_(f))=(i_(b)K_(b)m)/(i_(1)k_(f)m)`
so `i_(1)=1`
i.e. `AB` behaves as non-electrolyte at the f.p. of the solution