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Mole fraction of a non-electrolyte in aq...

Mole fraction of a non-electrolyte in aqueous solution is `0.07`. If `K_(f)` is `1.86^(@) "mol"^(-1)kg`, depression if `f.p.,DeltaT_(f),` is:

A

`0.26^(@)`

B

`1.86^(@)`

C

`0.13^(@)`

D

`7.78^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
Firstly we have to convert mole fraction into molality.
`"Molality"=(X_("solute"))/(X_("solvent")M_("solvent")//1000)=(0.07xx1000)/(0.93xx18)=4.18`
Now, `DeltaT_(f)=k_(f)m`
`=1.86xx4.18=7.78^(@)`.
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