Total vapour pressure of mixture of `1` mol of volatile component `A(P_(A^(@))=100mmHg)` and `3` mol of volatile component `B(P_(B^(@)=60 mmHg)` is `75mm`. For such case:

Options

A. there is positive deviation from Raoult's low
B. boiling point has been lowered
C. force of attraction between `A` and `B` is maller than that between `A` and `A` between `B` and `B`
D. All the above statements are correct.

Answer

D

Explanation

`P=P_(A).^(@)X_(A)+P_(B).^(@)X_(B)`
`(100)/(4)+(60xx3)/(4)`
`=70mmlt75mm` (experimental)
Thus, there is positive deviation (A) is true, mixture is more volatile due to decrese in b.p. Thus, (B) is true also force of attraction is decreased thus (C) is true.