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If relative decrease in vapour pressure ...

If relative decrease in vapour pressure is 0.4 for a solution containing 1 mol NaCl in 3 mol of `H_(2)O`, then % ionization NaCl is

A

`60%`

B

`50%`

C

`100%`

D

`40%`

Text Solution

Verified by Experts

The correct Answer is:
C
`RLVP=("i"n_(Nacl))/("i"n_(naCl)+n_(H_(2)o)`
`0.4=("i")/(i+3)`
so `i=2`
`because i=1+alpha` so `alpha=1` or `100%`
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