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At 40^(@)C, vapour pressure in Torr of m...

At `40^(@)C`, vapour pressure in Torr of methanol nd ethanol solution is `P=119x+135` where `x` is the mole fraction of methanol. Hence

A

vapour pressure of pure methanol is `119` Torr

B

vapour pressure of pure ethanol is `135` Torr

C

vapour pressure of equimolar mixture of each is `127` Torr

D

mixture is completely immiscible

Text Solution

Verified by Experts

`P=119x+135`
`x=1` for pure methanol.
so `P^(@)_("methanol")=119+135=254` Torr
But for pure ethanol `x=0`
so `P_("ethanol")^(@)=135` Torr
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