Two point charges `+8q` and `-2q` are located at `x=0` and `x=L` respectively. The location of a point on the x axis at which the net electric field due to these two point charges is zero is

Options

A. `2L`
B. `L/4`
C. `8L`
D. `4L`

Answer

A

Explanation

Due to two charges of opposite nature, E will be zero on the line joining the two charges and nearer to the charge of simaller magnitude.

`(K8Q)/x^(2)=(K2q)/((x-L)^(2))rArr x=2L`