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Short electric dipole of dipole moment P...

Short electric dipole of dipole moment P is placed at the centre of a ring of radius R having charge Q uniformly distributed on its circumference. The dipole moment vector is along the axis of the ring. Find force on the dipole due to the ring.

Text Solution

Verified by Experts

The correct Answer is:
`(PQ)/(4pi in_(0)R^(3))`
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Knowledge Check

  • A dipole of dipole moment P is kept at the centre of a ring of radius R and charge Q the dipole moment has direction along the ring due to the dipole is :

    A
    zero
    B
    `(kpQ)/(R^(3))`
    C
    `(2kpQ)/(R^(3))`
    D
    `(kpQ)/(R^(3))` only if the change is uniformly distributed on the ring .
  • An electric dipole of dipole moment p is placed in a uniform external electric field E. Then, the

    A
    toeque experienced by the dipole is `E xxp`
    B
    torque is zero, if p is perpendicular to E
    C
    torque is maximum, if p is perpendicular to E
    D
    potential energy is maximum, if p is parallel to E
  • As shown in the figure an electric dipole lies at a distance x from the centrr of a chargerd ring of radius R with charge Q uniformly distributed over it .The net force acting on the dipole is

    A
    `(aQq)/(4piepsilon_(0))(R^(2)-2x^(2))/(2piepsilon_(0)(R^(2)+x^(2))^(5//2))`
    B
    `(aQq)/(2piepsilon_(0))(R^(2)+2x^(2))/(2piepsilon_(0)(R^(2)+x^(2))^(5//2))`
    C
    `(aQq)/(4piepsilon_(0))(R^(2)+2x^(2))/(2piepsilon_(0)(R^(2)+x^(2))^(5//2))`
    D
    `(aQq)/(2piepsilon_(0))(R^(2)-2x^(2))/(2piepsilon_(0)(R^(2)+x^(2))^(5//2))`
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