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A sermicircular ring of radius R carries...

A sermicircular ring of radius R carries a uniform linear charge of `lamda`. P is a point in the plane of the ring at a distance R from centre O. OP is perpendicular to AB. Find electric field intensity at point P.

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The correct Answer is:
`(1)/(4pi in_(0))(lamda)/(R)ln(sqrt(2)+1)`
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