A uniform magnetic field B exists in a region of circular cross section of radius R. The field is directed perpendicularly into the plane of the figure. There is a tri- angular circuit ABC made of a uniform wire placed in the circular region. The triangle is a right angled isosceles tri- angle with equal sides `AB = BC = l`. The hypotenuse AC has its midpoint at the centre of the circle. Electrical resistance of the triangular circuit per unit length is`(r_(0))/(l)`. If the magnetic field is changed at a constant rate of `(dB)/(dt) = alpha`, find the potential difference between points C and A and that between B and A.

Answer

`V_(CA) = (l^(2)alpha)/(2(sqrt(2)+1)); V_(BA) = (l^(2)alpha)/(4(sqrt(2)+1))`