Consider two circuits given below. When switches `S_(1) and S_(2)` are closed at `t = 0`, the charge on capacitors `C_(1)` and `C_(2)` change with time as shown in graph 1 and 2 respectively. The current `i_(1)` and `i_(2)` in the two circuits change as shown in graph 1' & 2' respectively. Write the variation of current in the second circuit as function of time after the switch is closed at `t=0. e^(-1) =0.37`

Answer

`i=0.126 e^(-1000 t)` [t = in second]