Home
Class 12
CHEMISTRY
Upon treatment with ammoniacal H(2)S, th...

Upon treatment with ammoniacal `H_(2)S`, the metal ion that precipitates as a sulphide is

A

`Fe (III)`

B

`Al (III)`

C

`Mg(II)`

D

`Zn(II)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • QUALITATIVE ANALYSIS

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Passage Based Questions|6 Videos
  • QUALITATIVE ANALYSIS

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Fill in the blanks|1 Videos
  • QUALITATIVE ANALYSIS

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Assertion and Reason|2 Videos
  • PERIODIC CLASSIFICATION AND PERIODIC PROPERTIES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise COMPREHENSION_TYPE|3 Videos
  • S BLOCK ELEMENTS

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise True/False|1 Videos

Similar Questions

Explore conceptually related problems

Upon treatment with ammonical H_(2)s , the metal ion that precipitates as a sulfide is

A solution of Cu^(2+) Zn^(2+) Bi^(3+) . Mn^(2+) and Co^(2+) at pH = 1 is reacted with H_(2)S . Which ions will be precipitated as sulphide?