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1.82 g of a metal required 32.5 mL of N-...

1.82 g of a metal required 32.5 mL of N-HCl to dissolve it what is the equivalent weight of metal?

A

65

B

75

C

56

D

90

Text Solution

Verified by Experts

The correct Answer is:
C

`therefore " Meq. of metal"="Meq. of "HCL " or "1.82/Exx1000=32.5xx1`
`therefore " E"=56`
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