What weight of `NaCl` is added to one litre of water so that
`Delta"T"//"K"_("f")=1/500?`

Options

A. 5.85g
B. 0.585g
C. 0.0585g
D. 0.0855g

Answer

C

Explanation

For NaCl `"I"=2`
`"Or " Delta"T"_("f")="i"."K"_("f")."m"` lt brgt `Delta"T"_("f")//"K"_("f")=2."m"`
`"Or "1/500=2xx"m"`
Or molality`=1/1000" or " 1/1000"moles"` are dissolved `"Kg"^(-1)` of water or approximately`1/1000` moles are present in 1.0 litre of water (cosidering molarity and molality to be the same)
`therefore" Weight of NaCl"=1/1000xx58.5"g of NaCl"`
`=0.0585"g of NaCl."`