The specific conductivity of a `0.5` M aq. solution of monobasic acid `HA` at `27^(@)"C"` is `0.006` `"Scm"^(1)`. It’s molar conductivity at infinite dilution is `200` S `"cm"^(2)"mol"^(-1)`. Calculate osmotic pressure (in atm) of `0.5` M `HA`(aq) solution at `27^(@)"C"`. Given `R=0.08"L""-atm"//"K""-mol"`

Answer

12.72

Explanation

`Lambda_("m")^("C")=("K"xx1000)/"C"=(0.006xx1000)/0.500=12" S cm"^(2)"mol"^(-1)`
`Lambda_("m")^("0")=200"Scm"^(2)"mol"^(-1)`
`alpha=("Lambda"_("m")^("C"))/("Lambda"_("m")^("0"))=0.06`
For `HA`, `"n"=2`
`"i"=1+("n"-1)alpha`
`=1+(2-1)xx0.6`
`"i"=1.06`
`pi="i"xx"CRT"`
`pi=1.06xx0.5xx0.08xx300`
`pi=12.72"atm"`