Home
Class 11
PHYSICS
A soap bubble of radius r(1) is placed o...

A soap bubble of radius `r_(1)` is placed on another soap bubble of radius `r_(2)(r_(1) lt r_(2))`. The radius `R` of the soapy film separating the two bubbles is :

A

`r_(1) + r_(2)`

B

`sqrt(r_(1)^(2) + r_(2)^(2))`

C

`(r_(1)^(3) + r_(2)^(3))`

D

`(r_(2)r_(1))/(r_(2) - r_(1))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the radius \( R \) of the soapy film separating two soap bubbles of radii \( r_1 \) and \( r_2 \) (where \( r_1 < r_2 \)), we can use the concept of pressure differences due to surface tension. Here’s a step-by-step solution: ### Step 1: Understand the Pressure Inside the Bubbles The pressure inside a soap bubble is given by the formula: \[ P = P_0 + \frac{4\sigma}{r} \] where \( P_0 \) is the atmospheric pressure, \( \sigma \) is the surface tension, and \( r \) is the radius of the bubble. ### Step 2: Write the Pressure Equations For the smaller bubble (radius \( r_1 \)): \[ P_1 = P_0 + \frac{4\sigma}{r_1} \] For the larger bubble (radius \( r_2 \)): \[ P_2 = P_0 + \frac{4\sigma}{r_2} \] ### Step 3: Set Up the Pressure Difference Since the pressure inside the smaller bubble is greater than that inside the larger bubble, we can express the pressure difference when moving from the first bubble to the second bubble: \[ P_1 - P_2 = \frac{4\sigma}{r_1} - \frac{4\sigma}{r_2} \] ### Step 4: Relate the Pressure Difference to the Soap Film The pressure difference across the soap film is also given by: \[ P_1 - P_2 = \frac{4\sigma}{R} \] where \( R \) is the radius of the soap film. ### Step 5: Equate the Two Expressions Now we can set the two expressions for the pressure difference equal to each other: \[ \frac{4\sigma}{R} = \frac{4\sigma}{r_1} - \frac{4\sigma}{r_2} \] ### Step 6: Simplify the Equation We can cancel \( 4\sigma \) from both sides (assuming \( \sigma \neq 0 \)): \[ \frac{1}{R} = \frac{1}{r_1} - \frac{1}{r_2} \] ### Step 7: Find a Common Denominator To combine the fractions on the right side, we find a common denominator: \[ \frac{1}{R} = \frac{r_2 - r_1}{r_1 r_2} \] ### Step 8: Invert to Find \( R \) Taking the reciprocal gives us: \[ R = \frac{r_1 r_2}{r_2 - r_1} \] ### Final Answer Thus, the radius \( R \) of the soapy film separating the two bubbles is: \[ R = \frac{r_1 r_2}{r_2 - r_1} \]

To find the radius \( R \) of the soapy film separating two soap bubbles of radii \( r_1 \) and \( r_2 \) (where \( r_1 < r_2 \)), we can use the concept of pressure differences due to surface tension. Here’s a step-by-step solution: ### Step 1: Understand the Pressure Inside the Bubbles The pressure inside a soap bubble is given by the formula: \[ P = P_0 + \frac{4\sigma}{r} \] where \( P_0 \) is the atmospheric pressure, \( \sigma \) is the surface tension, and \( r \) is the radius of the bubble. ...
Promotional Banner

Topper's Solved these Questions

  • SURFACE TENSION

    RESONANCE|Exercise Exercise- 2 PART - II|15 Videos
  • SURFACE TENSION

    RESONANCE|Exercise Exercise- 2 PART - III|3 Videos
  • SURFACE TENSION

    RESONANCE|Exercise Exercise- 1 PART - II|17 Videos
  • STRING WAVES

    RESONANCE|Exercise Exercise|32 Videos
  • UNITS, DIMENSION & MEASUREMENT

    RESONANCE|Exercise Exercise|27 Videos

Similar Questions

Explore conceptually related problems

A soap bubble of radius r is placed on another bubble of radius 2r . The radius of the surface common to both the bubbles is

A soap buble of radius 1.0 cm is formed inside another soap bubble of radius 2.0 cm . The radius of an another soap bubble which has the same pressure difference as that between the inside of the smaller and outside of large soap bubble , in metres is

Two soap bubbles of radius r_(1) and r_(2) combine. Find radius of curvature of the common surface separating them.

A soap bubble of radius r is formed inside another soap bubble of radius R (gt r) . The atmospheric pressure is P_(0) and surface tension of the soap solution is T. Calculate change in radius of the smaller bubble if the outer bubble bursts. Assume that the excess pressure inside a bubble is small compared to P_(0) .

When two soap bubbles of radius r_(1) and r_(2)(r_(2) gt r_(1)) coalesce, the radius of curvature of common surface is

A soap bubble of raidus R is surrounded by another soap bubble of radius 2R , as shown. Take surface tension =S . Then the pressure inside the smaller soap bubble, in excess of the atmosphere presure will be

If a soap bubble of radius 3 cm coalesce with another soap bubble of radius 4 cm under isothermal conditions the radius of the redultant bubble formed is in cm

A soap bubble of radius 6 cm and another bubble of 8 cm coalesce under isothermal xonditions in vacuum. The radius of the new bubble is

A soap - bubble with a radius 'r' is placed on another bubbles with a radius R (figure). Angles between the film at the point of contact will be -

If two soap bubbles of equal radii r coalesce then the radius of curvature of interface between two bubbles will be