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The audible frequency for a normal human...

The audible frequency for a normal human being is `20 Hz` to `20 kHz`. Fuind the corresponding wavelengths if the speed of sound in air `320 m//s`.
(b) Find the phase difference between two position separated by `20 cm` at a particular instant.

Text Solution

Verified by Experts

The correct Answer is:
`16 mm, 16 m`
`lambda = (V)/(eta)`
`lambda_(max) = (320)/(20 Hz) = 16 m , lambda_(min) = (320)/(20 KHz) = 16 mm`.
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Knowledge Check

  • A transverse wave along a stretched string has a speed of 30 m/s and a frequency of 250 Hz. Then the phase difference between two points on the string 10 cm apart at the same instant is

    A
    0
    B
    `pi//2` rad
    C
    `5pi//3`
    D
    `8pi//3`

  • A wave of frequency 20 Hz is propagatinig is space with speed 200 m/s. the phase difference of the two points of wave separated by a distance 5 m is

    A
    `2pi` radian
    B
    `pi` radian
    C
    `(pi)/(3)` radian
    D
    `(pi)/(2)` radian

  • In stationary waves, distance between a node and its nearest antinode is 20 cm . The phase difference between two particles having a separation of 60 cm will be

    A
    Zero
    B
    `pi//2`
    C
    `pi`
    D
    `3 pi //2`
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