Home
Class 11
PHYSICS
The audible frequency for a normal human...

The audible frequency for a normal human being is `20 Hz` to `20 kHz`. Fuind the corresponding wavelengths if the speed of sound in air `320 m//s`.
(b) Find the phase difference between two position separated by `20 cm` at a particular instant.

Text Solution

Verified by Experts

The correct Answer is:
`16 mm, 16 m`
`lambda = (V)/(eta)`
`lambda_(max) = (320)/(20 Hz) = 16 m , lambda_(min) = (320)/(20 KHz) = 16 mm`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOUND WAVES

    RESONANCE|Exercise Exercise- 1 PART - II|30 Videos

  • SOUND WAVES

    RESONANCE|Exercise Exercise- 2 PART - I|25 Videos

  • SOUND WAVES

    RESONANCE|Exercise Board Level Exercise|33 Videos

  • SIMPLE HARMONIC MOTION

    RESONANCE|Exercise Exercise|28 Videos

  • STRING WAVES

    RESONANCE|Exercise Exercise|32 Videos

Similar Questions

Explore conceptually related problems

The audible range of a human ear is 20 Hz to 20 kHz. Convert this into corresponding wavelength range. The speed of sound at ordinary temperature is 340 m//s .

A sound wave of frequency 80 Hz is travelling with speed 320 m//s . (a) Find the change in phase at a given position in 400 ms (b) Find the phase difference between two positions seperated by 20 cm at a particular instant.

Knowledge Check

  • A transverse wave along a stretched string has a speed of 30 m/s and a frequency of 250 Hz. Then the phase difference between two points on the string 10 cm apart at the same instant is

    A
    0
    B
    `pi//2` rad
    C
    `5pi//3`
    D
    `8pi//3`

  • A wave of frequency 20 Hz is propagatinig is space with speed 200 m/s. the phase difference of the two points of wave separated by a distance 5 m is

    A
    `2pi` radian
    B
    `pi` radian
    C
    `(pi)/(3)` radian
    D
    `(pi)/(2)` radian

  • In stationary waves, distance between a node and its nearest antinode is 20 cm . The phase difference between two particles having a separation of 60 cm will be

    A
    Zero
    B
    `pi//2`
    C
    `pi`
    D
    `3 pi //2`

    • Similar Questions

    Explore conceptually related problems

    Two adjacent resonance frequency of an open organ pipe are 1800 and 2100 Hz . Find the length of the tube. The speed of sound in air is 330 m//s .

    Audible frequencies have a range 20 Hz to 20,000 Hz. Express this range in terms of wavelength lambda in air. Given velocity of sound in air is 330 ms^-1 .

    Audible ranges of frequencies is 20 Hz to 20,000 Hz. Find the range of wavelengths corresponding to this frequency. Given, velocity of sound = 340"m s"^(-1) .

    The range audible frequency for humans is 20 Hz to 20,000 Hz . If speed of sound in air is 336 m//s . What can be the maximum and minimum length of musical instrument. Based on resonance pipe.

    Frequency of audible sound waves ranges between 20 Hz and 20 KHz. If the velocity of sound in air is 320 m/s, the range of the wavelengths of the sound in air is

    Home
    Profile