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In an organ pipe the distance between th...

In an organ pipe the distance between the adjacent node is `4 cm`. Find the frequency of source if speed of sound in air is `336 m//s`.

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The correct Answer is:
`4.2 kHz`
`(lambda)/(2) = 4 xx 10^(-2)m , lambda = 8 xx 10^(-2)m`
`n = (V)/(lambda) = (336)/(8 xx 10^(-2)) = 4200 Hz = 4.2 KHz`
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RESONANCE-SOUND WAVES-Exercise- 1 PART - I
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