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A train is passing a stationary observer...

A train is passing a stationary observer at station with constant velcity. If the frequency observed by the person during its approches and recession are `2.2 kHz` and `1.8 kHz` respectively. Then find the velocity of train if the velocity of sound in air in air is `300 m//s`.

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The correct Answer is:
`V_(S) = 30 m//s`
`1.8 xx 10^(2) = (300)/(300 + v_(5)) xx f , 2.2 xx 10^(3) = (300)/(300 - V_(s))f rArr V_(s) = 30 m//s`
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Knowledge Check

  • Two trains A and B are approaching a platfrom from opposite directions .The siren in the station is making a sound at a frequency 4kHz.The passengers in trains A and B hear siren at frequencies 4.5 and 5kHz respectively.Then the velocities of the trains A and B are (velocity of sound in air =340 m/s)

    A
    42.5 m/s ,85m/s
    B
    75 m/s, 55 m/s
    C
    85 m/s, 8.5 m/s
    D
    42.5 m/s ,62.m/s

  • A source of sound attached to the bob of a simple pendulum execute SHM . The difference between the apparent frequency of sound as received by an observer during its approach and recession at the mean frequency of the source . The velocity of the source at the mean position is ( velocity of sound in the air is 340 m//s ) [Assume velocity of sound lt lt velocity of sound in air ]

    A
    `1.4 m//s`
    B
    `3.4 m//s`
    C
    `1.7 m//s`
    D
    `2.1 m//s`

  • A stationary source of sound is emitting sound of frequency 500Hz . Two observers A and B lying on the same line as the source, observe frequencies 480Hz and 530 Hz respectively. The velocity of A and B respectively are (in m//s ), speed of sound =300m//s .

    A
    `12,18`
    B
    `8,18`
    C
    `18,8`
    D
    `18,12`
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