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x=(at+b)^(n) where a, b and n are a real...

`x=(at+b)^(n)` where a, b and n are a real number then `(dx)/(dt)=an(at+b)^(n-1)`.

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Verified by Experts

`u=at+b and x=u^(n)`
`(dx)/(du)=n u^(n-1)`
`(du)/(dt)=a`
`(dx)/(dt)=(dx)/(du)xx(du)/(dt)=n(u)^(n-1)xxa=an(at+b)^(n-1)`
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