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It x=sin^(2)theta, then find (dx)/(dt) ...

It `x=sin^(2)theta`, then find `(dx)/(dt)` where `(d theta)/dt)=omega`

Text Solution

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`(dx)/(d theta)=2(sin theta)(costheta)=sin2theta`
`(dx)/(dt)=(dx)/(d theta).(d theta)/ (dt)`
`(dx)/(dt)=sin 2 theta.omega`
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