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A body is moving vertically upwards unde...

A body is moving vertically upwards under gravity such that its position from ground is given as `y=ut-(1)/(2)g t^(2)` . Find the max height reached by body.

Text Solution

Verified by Experts

`(dy)/(dt)=u-g t=0 ,t=(u)/(g)`
`(d^(2)y)/(dx^(2))=-glt0` (which is negative). So we get maximum height`y_(max)at" " t=(u)/(g)sec`.
`y_(max)=u((u)/(g))-(1)/(2)g((u)/(g))^(2)`
`(u^(2))/(2g)`
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