Suppose `A=B^(n)C^(m)` , where A has dimensions LT, B has dimensions `L^(2)T^(-1)`, and C has dimensions `LT^(2)` , Then the exponents n and m have the values:
(A) `2//3,1//3 " "` (B) `2,3 " "` (C)`4//5,-1//5 " "` (D) `1//5,3//5`
`(E)`1//2,1//2`

Explanation

To solve the problem, we need to find the values of the exponents \( n \) and \( m \) in the equation \( A = B^n C^m \) given the dimensions of \( A \), \( B \), and \( C \).

### Step-by-Step Solution:

1. **Identify the dimensions of \( A \), \( B \), and \( C \)**:
- \( A \) has dimensions \( [A] = LT \)
- \( B \) has dimensions \( [B] = L^2 T^{-1} \)
- \( C \) has dimensions \( [C] = LT^2 \)
...