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Given that in (alpha//pbeta )=alphaz//K(...

Given that in `(alpha//pbeta )=alphaz//K_(B)theta` where p is pressure, z is distance, `K_(B)` is Boltzmann constant and `theta` is temperature, the dimension of `beta` are (useful formula Energy`=K_(B)xx` temperature)
(A) `L^(0)M^(0)T^(0) " " (B)L^(1)M^(-1)T^(2) " " (C)L^(2)M^(0)T^(0)" "(D)L^(-1)M^(1)T^(-2)`

Text Solution

Verified by Experts

`ln((alpha)/(pbeta))=(alphaz)/(k_(B)theta)`
`[alphaz]=[k_(beta)theta] " "` Also`[alpha]=[pbeta]`
`[alpha betaz]=[k_(beta)theta]`
`[beta]=((k_(beta)theta))/((p z))=(ML^(2)T^(-2)K^(-1)K)/(ML^(-1)T^(-2)L)=L^(2)`
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