Young's modulus of steel is `19xx10^10 N/m^2`. Expres it indyne/cm^2. Here dyne is the CGS unit of force.

Explanation

The unit of Young's modulus is `N//m^(2)` .
This suggests that it has dimensions of `("Force")/(area)`.
Thus, `[Y]=[(F)/(L^(2))]=(MLT^(-2))/(L^(2))=ML^(-1)T^(-2)`.
`N//s^(2)` is in SI units.
So, `1 N//m^(2)=(1kg)(1m)^(-1)(1s)^(-2)`
and `1 "dyne"//cm^(2)=(1g)(1cm)^(-1)(1s)^(-2)`
So, `(1N//m^(2))/(1"dyne"//cm^(2))=((1kg)/(1g))=((1m)/(1cm))^(-1)((1s)/(1s))^(-2)`
`" "=1000xx(1)/(100)xx1=10`
0r, ` " " 1N//s^(2)=10"dyne"//cm^(2)`
or, `" " 19xx10^(10)N//m^(2)=19xx10^(11) "dyne"//cm^(2)`