The frequency `f` of vibrations of a mass `m` suspended from a spring of spring constant `k` is given by `f = Cm^(x) k^(y)` , where `C` is a dimensionnless constant. The values of `x and y` are, respectively,

Options

A. `x=(1)/(2), y=(1)/(2)`
B. `x=-(1)/(2) , y=(1)/(2)`
C. `x=(1)/(2) , y=-(1)/(2)`
D. `x=-(1)/(2) , y=-(1)/(2)`

Answer

B

Explanation

`f=cm^(x).k^(y)`
`[f]=[m^(x)][k^(y)]`
`rArr t^(-1)=M^(x)M^(y)T^(-2y)`
`x+y=0`
`y=(1)/(2) rArrx=(-1)/(2)`