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A particle moving with velocity v having...

A particle moving with velocity v having specific charge (q/m) enters a region of magnetic field B having width `d=(3mv)/(5qB)` at an angle `53^(@)` to the boundary of magnetic field. Find the angle `theta` in the diagram

A

`37^(@)`

B

`60^(@)`

C

`90^(@)`

D

none

Text Solution

Verified by Experts

The correct Answer is:
C
`R=(mv)/(qB)`
`d=R cos 53^(@)`

`rArr theta = 90^(@)`
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