When one computes the square root of the ratio of the permeability of free space to the permitivity of free space, one obtains `sqrt(mu_(0)/epsilon_(0))=337`. What is the unit of this quantity?

Options

A. farads
B. joules
C. volts
D. ohms

Answer

D

Explanation

Unit of `mu_(0)`= ohm sec/meter
`C^(2) = 1/(mu_(0)epsilon_(0))`
`rArr epsilon_(0) = 1/(C^(2) mu_(0))`
C=velocity of light
`xsqrt(mu_(0)/epsilon_(0)) = sqrt(mu_(0)^(2)C^(2))= mu_(0)C`
Unit of C = metre/sec.
Unit of `sqrt((mu_(0))/epsilon_(0)) =` unit of `mu_(0)C`= ohm sec/meter x meter/sec = Ohm.